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what are the solutions for the quadratic equation 5x^2 4x = 12?
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there is no sign between 5x^2 and 4x
its a minus sign sorry
5x^2-4X-12=0 =>5x^2-10x+4x-12=0 (x-2)(5x+2)
sparky, bnb answered your previous question incorrectly. you might want to look into that
5x^2-4x-12=0 (x-2)(5x+6)=0 x=2 or x=-6/5
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brackett has answered wrong!!!!!!!!!!!
that is incorrect, nancy
nancy is doing totally wrong....
first thing....5x-6=0 does not give u x=6
(x+2)(5x-6)=5x^2+4x-12.........
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he said it is -4x......
\[5x ^{2}-4x-12=0\] \[5x ^{2}-10x+6x-12=0\] \[5x(x-2)+6(x-2)=0\] \[(5x+6)(x-2)=0\] x = -6/5 x=2
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