Please help !!! Simplify: 2(a^2b^-1)^2 X (4ab^3)^4
4a^4b^-2*216a^4b^12=864a^8b^10
How could 4a^ 4b be ?
sorry that would be 2a^4b^-2
2a^4b^-2*216a^4b^12=432a^8b^10
Thank you can you help me with the other questions too ?
yes...i will try.....
Okay i dont get this one : -7(2x^2+3x-2)-(x^2+4) Can you show how you did it so that i can see how to do it ?
-14x^2-21x+14-x^2-4 =-15x^2-21x+10
oh btw for previous problem...4^4 is 256 not 216 so it would be 512 instead of 432
sorry...zealindaus...
Yeh thanks I didnt bother to check if it was right. 3-(2X-1)(3X^2+X-3)-4
3-(6x^3+2x^2-6x-3x^2-x+3)-4 =-6x^3+x^2+7x-4
Thanks I hope its right ill check over them later. (2x+3y)(x^2-4xy+3y^2)
2x^3-5x^2y-6xy^2+9y^3
3(x+4)
3x +12
Lol yeh woop wooop got that one right XD
Without using a calculator and showing all ur calculations, determine between which 2 integers \[\sqrt{17}\] lay
\[\sqrt{16} = 4\] \[\sqrt{25}=5\]
Is this right ? 4xy + 6xyz = 2(2xy)+(3xyz) ?
Its factorizing btw
4xy + 6xyz = 2xy( 2+3z)
sweet_blues u r not right...that will be 2[(2xy)+(3xyz)]
Yeah i got it now thanks sorry people its the first time i have done factorizing and simplifying.
you should not be sorry............
we also make mistakes....
Okays well i have a few more questions to do before bed time if you could help me with these itd be great. I dont think you can factorize this one : mn+3n+4m+12 ?
n(m+3)+4(m+3)=(m+3)(n+4)
so how was the factorisation????
Idk my teacher just told me to do these for homework but her explenation of how to do them sucked. Says its factorizing on my work sheet ?
haven't u understand the factorisation process?
Last one is 3-3x^2y^2 And i kinda do but finding it hard to use them.When u guys give me the awnsers i look at the question again and work out how u got the awnser u got.
\[3-3x^2y^2=3(1-x^2y^2)=3((1)^2-\[3(1+xy)(1-xy)\](xy)^2)\]
Wow dont you rekon thats a bit hard for a year 7 class
if u practice a lot u will find it easy...
Thanks dude, there was a few of solve x problem i was having trouble with yest wanna have a look ?
happy to notice that u r my fan...
5x-2=2x+10 3(x+7)= -2(x-9) x^2+6x-13=14 And no problem ur pure genuis man. Im more into literature than math >.<
ist one 3x-12=3(x-4) 2nd one 5x-3 3rd one x^2+6x-27 x^2+9x-3x-27 (x+9)(x-3)
for the second one 3(x+7)=-2(x-9) 3x+21=-2x+18 3x+2x+21-18=0 5x+3=0
i think u need the factorisation....
Nah ur supose to solve x lol..
ok...
1 st one 5x-2=2x+10 5x-2x=10+2 3x=12 x=12/2 x=4
2nd one 5x+3=0 5x=-3 x=-3/5
3rd one (x+9)(x-3)=0 x=-9 or 3
oh okay yup thanks. For this one i dont know what she wants me to write ? the degrees or what?
1.1 a hypotenuse 1.2 b hight 1.3 c base 1.4 d right angle
Okay Can you explain how to do this one =/
b=sqrt(119^2-59^2)=103.34 c=sqrt(b^2+41^2)=111.18
sqrt ?
square root
Oh riiiighto Sorry its really late I am really clueless about these ones >.<
i can give u clue but u have to do it by urself..
gradient finding formula is \[\frac{y_1-y_2}{x_1-x_2}\]
Sure just dont get angry if i get is wrong like i said its really late and it have to be in by tomarrow.
pm = 3 - -2 -4 - -5 am i even on the right path ?
yes ur right
yes...
I dont know what to do next tho =C
ur right...the slope is 5
So thats the awnser.. ? no = 3- -2 5 + 4
\[\frac{3-(-2)}{-4-(-5)}=\frac51=5\]
similarly for NO it comes 5 and for MN and PO it is 0 so MNOP is a parallelogram.
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