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Mathematics 24 Online
OpenStudy (anonymous):

Put x^2+5x-6=2x-4 into ax^2+bx+c=0??

OpenStudy (anonymous):

Is it x^2+3x-10

OpenStudy (anonymous):

rearranging the equation we hav, x^2+3x-2=0; therefore we hav a=1,b=3 and c=-2.

OpenStudy (anonymous):

wen u bring -4 the other side it changes to +4 and hence -6+4=-2

OpenStudy (anonymous):

Oh, yes okay. so then it is 1x^2+3x-2

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