Question

find the rate of change of V if;

V = x^2 y^3

x=cosbt and y=sinbt

Answer 1

V=x^2*y^3
and x and y are functions of t.
so now , dv/dt=2x*y^3*dx/dt+3y^2*x^2*dy/dt
u know dx/dt=-bsin(bt) and dy/dt=bcos(bt) ,
substitue and get the answer.
see i've done only chain differentiation. :)