Question

5m^2-11m-3=0 solve by using the quadratic formula

Answer 1

i tried doing them myself and got them wrong so plzzz help me

Answer 2

\[m^2-11m-3=0\]
\[a=5,b=-11,c=-3\]

Answer 3

formula is
\[\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]

Answer 4

ty

Answer 5

we plug in the numbers and get
\[\frac{-(-11)\pm\sqrt{(-11)^2-4\times 5\times (-3)}}{2\times 5}\]

Answer 6

the roots are, m=(11+sqrt(181))/10 and m=(11-sqrt(181))/10

Answer 7

now comes the computation
\[\frac{11\pm\sqrt{121+60}}{10}\]

Answer 8

\[\frac{11\pm\sqrt{181}}{10}\]

Answer 9

and if i didn't make an arithmetic mistake that is it!