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find solutions for 9x^2-81=0
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x = 3 or -3
x^2=9 and so u get x=+3 and x=-3
x^2-9 (x+3)(x-3)=0
(3x+9)(3x-9) so x = -9 or 9
what about for x^2-9=0, will that also be -3 and3
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yes
use the difference of 2 squares why? 9x^2 is a square and 81 is a square difference = - sqr root 9x^2 =3x sqr root 81=9 answers are solutions to (3x+9)(3x-9)=0 3x+9=0 implies 3x=-9 implies x=-3 and 3x-9 implies 3x=9 implies x=3 answers as given earlier x=3 or -3
x^2-9=0 sqr root x^2 is x sqr root of 9 =3 0=(x+3)(x-3) x=3 or -3 yes the answers are the same.
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