Question

Evaluate lim x^2+x
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x->-1 x^2-1

Answer 1

factor and cancel

Answer 2

\[\frac{x^2+x}{x^2-1}=\frac{x(x+1)}{(x+1)(x-1)}=\frac{x}{x-1}\]

Answer 3

then replace x by -1 to get \[\frac{1}{2}\]