Question

Find the fifth term of (1/2h-3j)⁸...just need some guidance! thanks!

Answer 1

For the binomial,\[(x+y)^n\]the expansion will be\[\sum_{k=0}^{n}x^k y^{n-k}\]The fifth term will be that term for which k = 4, since the expansion begins at zero. Hence, \[(8 \ 4)(1/2h)^4(-3j)^4=\frac{8!}{4!4!}(1/2h)^4(-3j)^4\]and you can clean it up :)