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Mathematics 7 Online
OpenStudy (anonymous):

x^2-13x+12=0

OpenStudy (anonymous):

(X-12)(X-1) X=12 OR X=1

OpenStudy (anonymous):

Do you need to factor it?

OpenStudy (anonymous):

okay thanks...

OpenStudy (anonymous):

no i got it, thanks!

OpenStudy (anonymous):

(x-12)(x-1)=0 so x-12=0 x=12 and x-1=0 x=1 so x= 12 and x=1

OpenStudy (anonymous):

Oh alright. :D

OpenStudy (anonymous):

:)

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