Question

x^2+y^2-2x+6y+3=0 this equation is equivalent to ....
1. (x-1)^2 +(y+3)^2=-3
2. (x-1)^2+(y+3)^2=7
3. (x+1)^2+(y+3)^2=7
4. (x+1)^2+(y+3)^3=10

help please. explain steps please

Answer 1

u complete squares, ans is 2.

Answer 2

can you show me how you did it?

Answer 3

do you know how to complete a square?

Answer 4

group the terms like this
\[x^2-2x+y^2+6y=-3\]

Answer 5

then for the x think "half of -2 is -1, and \[(-1)^2=1\]" also think "half of 6 is 3, and \[3^2=9\] "
then write

\[ (x-1)^2+(y+3)^2=-3+1+9\]