x^2+y^2-2x+6y+3=0 this equation is equivalent to ....
1. (x-1)^2 +(y+3)^2=-3
2. (x-1)^2+(y+3)^2=7
3. (x+1)^2+(y+3)^2=7
4. (x+1)^2+(y+3)^3=10

help please. explain steps please

Question

x^2+y^2-2x+6y+3=0 this equation is equivalent to .... 
1. (x-1)^2 +(y+3)^2=-3
2. (x-1)^2+(y+3)^2=7
3. (x+1)^2+(y+3)^2=7
4. (x+1)^2+(y+3)^3=10

help please. explain steps please

anonymous · Answer

u complete squares, ans is 2.

anonymous · Answer

can you show me how you did it?

anonymous · Answer

do you know how  to complete a square?

anonymous · Answer

group the terms like this 
$$x^2-2x+y^2+6y=-3$$

anonymous · Answer

then for the x think "half of -2 is -1, and $$(-1)^2=1$$" also think "half of 6 is 3, and $$3^2=9$$ "
then write

$$ (x-1)^2+(y+3)^2=-3+1+9$$