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OpenStudy (anonymous):
ln(1/x)+ln(2x^3)=ln^3 solving for x.
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OpenStudy (anonymous):
retype the ques please
OpenStudy (anonymous):
ln(1/x)+ln(2x^3)+ln^3 trying to find x
OpenStudy (anonymous):
what do u mean ln^3 ?
OpenStudy (watchmath):
Is it ln x^3?
OpenStudy (anonymous):
no it's ln3 sorry
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OpenStudy (anonymous):
x = sqrt(3/2)
OpenStudy (anonymous):
yea i have the answer just don't know how to do it!
OpenStudy (anonymous):
use log properties
OpenStudy (anonymous):
is the next step ln(-x)+3ln2x=ln3?
OpenStudy (anonymous):
google logarithm, see the wikipedia article
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OpenStudy (anonymous):
ok thanks
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