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Mathematics 4 Online
OpenStudy (anonymous):

ln(1/x)+ln(2x^3)=ln^3 solving for x.

OpenStudy (anonymous):

retype the ques please

OpenStudy (anonymous):

ln(1/x)+ln(2x^3)+ln^3 trying to find x

OpenStudy (anonymous):

what do u mean ln^3 ?

OpenStudy (watchmath):

Is it ln x^3?

OpenStudy (anonymous):

no it's ln3 sorry

OpenStudy (anonymous):

x = sqrt(3/2)

OpenStudy (anonymous):

yea i have the answer just don't know how to do it!

OpenStudy (anonymous):

use log properties

OpenStudy (anonymous):

is the next step ln(-x)+3ln2x=ln3?

OpenStudy (anonymous):

google logarithm, see the wikipedia article

OpenStudy (anonymous):

ok thanks

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