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16s^6-2p^6 factor
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2{(2s^2)^3-(p^2)^2}=2(2s^2-p^2)(4s^2+2s^2p^2+p^4)
is there a piece missing in this?
16s6−2p6 2( 8s6−p6 ) ==2(2s-p)(4s^2+\[2s ^{2}p ^{2}\]+p^4)
\[2(8s ^{6}-p ^{6)}\]\[2(2^{3}s ^{6}-p ^{6})\]\[2(2s ^{2}-p ^{2})(4s ^{4}+2p ^{2}s ^{2}+p ^{4})\]
I'm sure correct answer
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