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Mathematics 16 Online
OpenStudy (anonymous):

peirmeter of a sign thr perimeter of a rectangular sign is not to exceed 50ft the length is to be twice the width. what widths will meet these conditions

OpenStudy (anonymous):

l=2w and 2(l+w)<50 and so u get w<50/6

OpenStudy (anonymous):

width x lenth 2x 2(x+2x)<50 3x<25 x<25/3=8.333

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