Question

2x^2 + x +4 =0

wt=rite quation in standard form then identify a,b, and c

Answer 1

2x^2+x+4=0
=>x^2+x/2+2=0 and so u get a=1 ,b=1/2 and c=2.

Answer 2

\[2x ^{2}+x+4=0\]
By simplifying this you will \[x ^{2}+x/2+2=0\]
You can say it as \[ax ^{2}+bx+c=0\]
so a=1, b=1/2 and Constant C=2

Answer 3

ok how bout a negative like -3x^2 - 2 = x^2 + 3x

Answer 4

Again you have to simplify it do it as the same practice..if there is any doubts can ping me