Question

solutions to 5x^2-2x+16=4x^2+6x

Answer 1

is it -4?

Answer 2

x=4,4
do u need full solution

Answer 3

I don't think i do. just numbers. so 4 and -4? but isn't this a perfect square since root 16 is 4?

Answer 4

5x^2-4x^2-2x-8x+16=0
x^2-8x+16=0
(x-4)(x-4)=0
therefore
x=+4,+4

Answer 5

so just 4 then?

Answer 6

s just 4

Answer 7

Here is the detailed solution:-
\[5x ^{2}-4x ^{2}-2x-6x+16=0\]
\[x ^{2}-8x+16=0\]
\[x ^{2}-4x-4x+16=0\]

Or you can get roots of any equation by this formula.. \[-b \pm \sqrt{b ^{2}-4ac}/2a when a \neq0\]
you can x=-4,4

Answer 8

Oops sorry +4 only