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OpenStudy (anonymous):
solutions to (x-2)^2=16? help?
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OpenStudy (anonymous):
so far I have gotten x^2-4=16
OpenStudy (anonymous):
\[x=\pm4+2\]
OpenStudy (anonymous):
@gblover11...ur equation has some error...the equation is x^2-4x+4=16, check urs...
OpenStudy (anonymous):
(x-6)(x+2)=0 therefore x=6,x=-2
OpenStudy (anonymous):
you mean what I have worked out is wrong?
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OpenStudy (anonymous):
yes...post ur work,we'll tell u wer u went wrong :)
OpenStudy (anonymous):
I did (x-2)^2 and got x^2-4=16
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