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solutions to (2x+3)^2=10?
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x=(-3+-sqrt(10))/2
-squareroot 10-3/2 and pos. squrroot
\[(2x+3)^2=10\] \[2x+3\pm\sqrt{10}\] \[2x=-3\pm \sqrt{10}\] \[x=\frac{-3 \pm\sqrt{10}}{2}\]
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