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Please help. These two points determine a line: (0,3) and (2,5). Which of these other points , (4,7) , (4,8) , (4,10) Are also on the line ?
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do you know parametric equations ?
(4,7) lie on the line. the line equation is x-y+3=0.
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woah, parametrics? slope=1, y-3=1(x-0) --> y=x+3, 7=?4+3 yes.
What ?
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just get the equation of the line from the two points using the formula (y-y1)=m(x-x10 tke any one of the point as (x1,y1) m=(y1-y2)/(x1-x2) find m
not really, x = 2t y = 3 + 2t , t is on real
rise = 5-3=2, run = 2-0=2, slope = 2/2=1, point slope form: point (0,3) y-3=1(x-0) can be rearranged to y=x+3 then enter the three points to see if any of them make sense, and (4,7) does.
f(x) = x+3 (x,f(x)) (4,f(4)) (4,7)
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