Question

please help me.......

Answer 1

with what

Answer 2

\[\sqrt{3+a \sqrt{3=a}}\]

Answer 3

sorry at the end it was suppde to be 3-a

Answer 4

\[\sqrt{3+a(3-a)^{\frac{1}{2}}}=(3+a(3-a)^{\frac{1}{2}})^{\frac{1}{2}}\]\[(3+a)^{\frac{1}{2}}(3-a)^{\frac{1}{4}}\]\[\sqrt{3+a}\sqrt[4]{3-a}\]\[a=3\]\[a=-3\]