The perimeter of a rectangle is 56 inches. The length is 4 more than 3 times the width. What are the dimensions of the rectangle?
A) L+w=56
L=3w+4
B) L+w=56
W+4=3L
C) 2L+2W=56
W=3L+4
D) 2L+2W=56
L=3W+4

Question

The perimeter of a rectangle is 56 inches. The length is 4 more than 3 times the width. What are the dimensions of the rectangle? 
A)	L+w=56
L=3w+4
B)	L+w=56
W+4=3L
C)	2L+2W=56
W=3L+4
D)	2L+2W=56
L=3W+4

anonymous · Answer

l=22 and b=6

ans d

question repeated

anonymous · Answer

yeah but i forgot to show the choices

anonymous · Answer

and i still dont know how you got to that certin answer ?? like how did you slove for the probelm

anonymous · Answer

ok i c how u got it ow i just tried how to slove it :) my bad

anonymous · Answer

to solve first  we have to take the variable.

since length depends on the breadth

take breadth=x

hence the length is 4 more than 3 times  width. it becomes 3x+4

apply  the procedure  given previously

anonymous · Answer

did you  get that