Question

Evaluate:

lim (4+h)^2-16 / h
h->0

Answer 1

expand it out if its helpful

Answer 2

that's what i'm having trouble with

Answer 3

\[16+h^2 +8h-16 \over h\]

Answer 4

How abt Hopital's theorem?

Answer 5

\[\frac{h^2}{h}+\frac{8h}{h}\]

Answer 6

\(h +8=8\) when h=0

Answer 7

Where does the 8h come from?

Answer 8

from opening the (4+h)^2

Answer 9

(4+h)^2

4+h
4+h
------
16 +4h
+4h +h^2
------------
16 +8h +h^2