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solve the logarithmic log base6 (4x-9) = log base6 x
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please , thats my final exam ,,, need help
I believe we can raise both sides to by 6 and thus end up with: 4x-9=x, next we subtract x from both sides giving us: 3x-9=0. then add 9 to both sides and finally divide both sides by three: x=3
\[4x-9=x\] Next subtract x from both sides: \[3x-9=0\] Then: add 9 to both sides: \[3x=9\] Finally divide both sides by three: \[x=\]
x=3*
what do you think?
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thanx alot , i appreciated
ur smart :)
if you really wan to thank me, you should click the good answer button :)
sure
Thank you
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ur welcome, thank u thank u thank u
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