Question

x^2 - 16/ x^2+4x+3 / x-4/x+1

Answer 1

first flip the second one
\[\frac{x^2-16}{x^2+4x+3}\times \frac{x+1}{x+4}\]

Answer 2

ten factor and cancel
\[\frac{(x-4)(x+4)(x+1)}{(x+3)(x+1)(x+4)}=\frac{x-4}{x+3}\]

Answer 3

thanx

Answer 4

yw