Mathematics
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OpenStudy (anonymous):
Find all real number solutions 3x^-2+7x^-1+2=0 ...
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OpenStudy (anonymous):
what if i find artificial solutions instead of real :P
OpenStudy (anonymous):
lol i dont think that will work... but i sure wish!
OpenStudy (anonymous):
multiply by x^2 both sides
OpenStudy (anonymous):
you'll get:
2x^2+7x+3=0
solve it
OpenStudy (anonymous):
x=-3 & x=-1/2
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OpenStudy (anonymous):
k thanks! ill try and see if i can get the same!
OpenStudy (anonymous):
Good luck:)
myininaya (myininaya):
u=x^(-1)
u^2=x^(-1*2)=x^(-2)
3u^2+7u+2=0
3u^2+6u+u+2=0
3u(u+2)+(u+2)=0
(u+2)(3u+1)=0
u=-2
u=-1/3
but u=x^(-1)
x^(-1)=-2
x=-1/2
x^(-1)=-1/3
x=-3
OpenStudy (anonymous):
THANK YOU
OpenStudy (anonymous):
a quadratic in
\[
\frac{1}{x}\]
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OpenStudy (anonymous):
oh myininaya got it! no surpise
myininaya (myininaya):
lol
OpenStudy (anonymous):
now if would only write in latex i could read it!
myininaya (myininaya):
satellite i want to show off
i want to show you my logic skills
follow me if you can
OpenStudy (anonymous):
are you posting a question?
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myininaya (myininaya):
no
you have to go to my name on the homepage and quick where im at
hope it works
such a lag site
OpenStudy (anonymous):
i;ll try