Question

what is the equation of the line that is perpendicular to y=2/3x -6 and passes through the point (6,-3)?

Answer 1

slope is
\[-\frac{3}{2}\] point is (6,-3) use
\[y-y_1=m(x-x_1)\]

Answer 2

to get
\[y-(-3)=\frac{3}{2}(x-6)\]

Answer 3

multiply out to get
\[y+3=-\frac{3}{2}x+9\] or
\[y=-\frac{3}{2}x+6\]

Answer 4

wait so the final answer is wut?