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16v^6-2p^6 factor
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2{(2v^2)^3-(p^2)^3} =2(2v^2-p^2)(4v^4+2V^2p^2+p^4)
taking two common 2(8v^6-p^6) 2((2v)^3-(p)^3)
use the a^3-b^3=(a-b)(a^2+ab+b^2) rule
soooo many people here to help :) im logging out and i gotta do my own homework lol nice meeting u guys XD
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