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Mathematics 8 Online
OpenStudy (anonymous):

x^2+2x-3=0 solve

OpenStudy (anonymous):

3,-1

OpenStudy (anonymous):

(x+3)(x-1)=0 x=-3,1

OpenStudy (anonymous):

dipankar you are wrong

OpenStudy (anonymous):

(x-3)(x+1)=0

OpenStudy (anonymous):

(x-3)(x+1)=x^2-2x-3.....so dherraj..... i think u are enough intelligent to identify it..

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