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OpenStudy (anonymous):
x^2+2x-3=0 solve
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OpenStudy (anonymous):
3,-1
OpenStudy (anonymous):
(x+3)(x-1)=0 x=-3,1
OpenStudy (anonymous):
dipankar you are wrong
OpenStudy (anonymous):
(x-3)(x+1)=0
OpenStudy (anonymous):
(x-3)(x+1)=x^2-2x-3.....so dherraj..... i think u are enough intelligent to identify it..
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