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Mathematics 6 Online
OpenStudy (anonymous):

what is the eccentricity of circle? How?

OpenStudy (anonymous):

zero...

OpenStudy (anonymous):

for a circle a=b so\[e=\sqrt{1-(\frac ba)^2}\]=0

OpenStudy (anonymous):

hello chutzpah have u understood?

OpenStudy (anonymous):

ya thanx.

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