Solve, assuming a linear equation fits the situation. The value of a graphing calculator is $225. After 2 years, the value of this calculator is $160. Find the value of the calculator after 5 years. (HINT: Let the time now be 0, the time in two years be 2, and the time in five years be 5.)
to get the linear equation we have to get the slope and the starting y value (whats it called in english?) starting y is obviously 225 slope is (160-225)/2 = -32.5 so the equation would be: f(x)=-32.5x+225 with x being years and f(x) being the value after x years. so after 5 years its value would be: f(5)=-32.5*5+225=62.5 so its value after 5 years would be 62.5$
62.5 is rong ... i typed it in and it said it was rong
62.5 is rong ...i typed it on and it said it was rong
Try typing in 162.5.
call me over delaine i'm bored.
are you sure? in 2 years it lost $225-$160=$65 value. so in 1 year it loses $65/2 = $32.5 (assuming a linear equation). so in 5 years it loses $32.5*5=$162.5. so after 5 years it has $225-$162.5=$62.5
Make x the price of the calculator at year 0 x=225 Year 2 equation. Y represents the year x=160+2y Solve simultanoeusly 225-160+2y=0 62=2y 32.5*5= 162.5....... Yeah the answer should be $62.5
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