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Evaluate the limit as x goes to 5 from the left side: this time absolute in denom
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I get -1
correct :)
want to ensure my theory is correct
yea temme the theory...
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because we are coming form the left side the absolute value will take a the negative value as in -5 not the positive vaklue of 5
its -1
ur theory is right :)
you are seeing these very often. i hope you recognize them as \[\frac{|x-5|}{x-5}=1\] if x > 5 and \[\frac{|x-5|}{x-5}=-1\] if x < 5
the absolute was in the the denom though?
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pls explain if I missed something sat - thanks!
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