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Mathematics 16 Online
OpenStudy (anonymous):

Factor completely. x^3+5x^2+6x

OpenStudy (anonymous):

(x)((x+3)(x+2)

OpenStudy (anonymous):

so simple....

OpenStudy (anonymous):

jst wait

OpenStudy (anonymous):

answer plz

OpenStudy (anonymous):

dheeraj is correct

OpenStudy (anonymous):

it is x(x+2)(x+3)

OpenStudy (anonymous):

yah a brcket extra in my ans

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