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Mathematics 15 Online
OpenStudy (anonymous):

Simplify in terms of cos θ. (1+tan^2θ)/(1-tan^2θ)

OpenStudy (anonymous):

I hope u knw that tan=sin/cos?

OpenStudy (anonymous):

1/cos (2theta)

OpenStudy (anonymous):

1/ (2cos^2 theta - 1)

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