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determine the mean, median, mode, and midrange of the set of data. Round your answer to the nearest tenth 4, 6, 10, 12, 10, 9, 365, 40, 37, 8
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mean = 50.1; median = 10; mode = 10
mode = 10 median = 10 mean = 50.1 yep
the midrange is 361 perhaps?
or do we count that 365 is an outlier and ignore it?
not sure amis -
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i think we can count that as an outlier
so midrange is either 36 or 361 :)
i think so
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