Question

solve: 4x^2+4=0

Answer 1

subtract 4 from both sides:
\[4x ^{2}=-4\]

Answer 2

x^2+1=0
x^2=-1
x=+ or - i

Answer 3

\[x ^{2}=-1\]
x=+/-i

Answer 4

x = -i and x= i

it has imaginary roots

Answer 5

thanks..whats about x^2-x+8=0

Answer 6

myin and inik are making a basic mistake
\[\sqrt{-1}=i\]

Answer 7

i got + or - i

Answer 8

for x^2 - x +8 = 0 again u hv imaginary roots

1 iroot31 1 iroot31
x = ---- + ------- and ----- - --------
2 2 2 2

Answer 9

@myininaya

what is root of -1 ????? You cannot take root of negative numbers !!!

Answer 10

sqrt{-1} is i
which i have above!

Answer 11

@kate

ans for first question is x= i and x = -i

Answer 12

which is what i got
i dont understand you

Answer 13

@myininaya and inik

Sorry, i commented on your ans as wrong because yr answers looked like 1 to me instead of i !!! My mistake .....

Answer 14

lol i was like wtf

Answer 15

lol ok