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Mathematics 19 Online
OpenStudy (anonymous):

trying to simplify this expression (x^2y^6)1/2 over (-2xy)^3

OpenStudy (anonymous):

\[{x^2y^6 \over 2}\over {-2x^3y^3}\]

OpenStudy (anonymous):

Trying to understand. So for the denominator you distribute the exponent? What about the 1/2?

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