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The picture inside a frame is 3 in. longer than it is wide, and the frame itself has a width of 2 in. on each side of the picture. If the area of the picture including the frame is 108 in2, find the dimensions of the outside edge of the frame.
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let width of inner frame = x (x + 2)(x + 2 + 3) = 108 (x + 2)(x + 5) = 108 x^2 + 7x + - 98 = 0 x = 7. so dimensions are 9 and 12...
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