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Translate the following sentence into an algebraic equation. Nineteen minus a number n is 4 more than the sum of 8 and n divided by 3. A. 19 - n = n/3 + 8 + 4 B. 19 - n = 8/n + 3 + 4 C. 19 - n = (n + 8)/3 + 4 D. n - 19 = (n + 8)/(3 + 4)
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19-n = (n+8)/3 + 4
C
i mean c
could be either a or c... depends if you want the sum of 8 and n and divide that by 3 or the sum of 8 and (n divided by 3)
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