Question

i just need someone to check the answer on this problem i got x=.3090 and x=-.8090 i used the quadratic formula and the problem is : 4x^2=1-2x

Answer 1

4x^2 = 1 -2x

4x^2 +2x -1 = 0

\[\frac{-2}{2(4)} \pm\frac{\sqrt{4-4(-1)(4)}}{2(4)}\]

Answer 2

\[{-1\over4}\pm \frac{\sqrt{20}}{8}\]
\[-\frac{1}{4}\pm\frac{2\sqrt{5}}{8}\]

Answer 3

\[\frac{-1\pm \sqrt{5}}{4}\]
is what I get.....

Answer 4

0.3090 .. is abt one of them so Id say you did good ;)

Answer 5

-0.8090 is the other

Answer 6

yay! lol thanx i wasnt sure!