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OpenStudy (keke):
simplify; 2+√(3) over 2-√(3)
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OpenStudy (anonymous):
oh!!
OpenStudy (anonymous):
rastionalise it and so u'll get, 7+4sqrt(7)
OpenStudy (anonymous):
multiply top and bottom by \[2+\sqrt{3}\] the denominator will be 1, and the numerator will be what brackett wrote
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