Question

x-3 (underneath the radical) = 2

a)x= -1
b) x = 1
c) x = 5
d) x = 7
?

Answer 1

\[\sqrt{x-3}=2 *\]

Answer 2

square both sides and u get x-3=4. so x=7.

Answer 3

but when yu square 3 and then square 2
9 - 4= 5 , so wouldnt it be c?

Answer 4

2nd question . . ^