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if one root of 5x^2+13+k is reciprocal of other. find k.
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a*1/a=k/5 k=5
how it is possible
the product of the roots of a quadratic equation is c/a where the equation is ax^2+bx+c=0 here a=5,b=13 and c=k
how b=13 it is constant
it must be 13x
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otherwise x^2=-(13+k)/5 if x^2=a^2 then x=a,-a not reciprocal...
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