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find the 22nd term of the arithmetic sequence 101,105,109,113
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185
t(n) = 101 + (n-1)4
all yu freakin do is go up 4 every time..dont be lazy! yu can do that urself!!!1!!
i did it in 2 seconds
claqe you are offically banned from answeing any of my questions
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oooo so.! do i care/
neither do i
ok then...just stay in school and do nothing! i bet yu are in summer school
A{0} = ? A{1} = A{0} + 4 = 101 A{2} = A{0} + 4 + 4 = 105 A{3} = A{0} + 4 + 4 + 4 = 109 A{n} = A{0} +4n 101 = A{0} + 4 ; A{0} = 107 A{n} = 107 + 4n .... i did it yay!!!
......lol almost 101 - 4 = 97 not 107....
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i do do all my work so talk wat you know.. that you don't know DON'T say nun.!
kudos to you amistre64 for trying :)
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