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Mathematics 19 Online
OpenStudy (keke):

simplify; 10√(8)+2√(2)

OpenStudy (anonymous):

\[22\sqrt{2}\]

OpenStudy (angela210793):

20sqr2+2sqr2=22sqr2

OpenStudy (anonymous):

. root 8 is the same as root 4 root 2 right? it becomes 10*root4root 2 2 root 2 just remains as it is you get 20root2+2root2 since root 2 is common factor it out answer becomes 20root2

OpenStudy (anonymous):

answer is 22root 2

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