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Find inverse transform of F(s)=(10s)/(4s^2+36)
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On the bottom, factor out the 4, then pull out the 10, you'll get: 10/4 times s/(s^2+8) so when you do inverse transform you get: \[f(t)=(5 / 2) *cos \sqrt{8} * t\] I think this is correct, but it's been a while , so you might want to check my work...
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