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16y^5-24y^4-40y^3
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\[16y^5-24y^4-40y^3\]
what do you want to solve for msmith?
how do u get the common factor
what does everything have in common?
y^3(16y^2 -24y -40) ; what do the numbers have in common? i see that 4 divides them all
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4y^3(4y^2 -6y -10) now 2 also works so divide it out 8y^3(2y^2 -3y -5)
factor out the greater common factor
you can work it in smaller steps; and when you get to the end of it, youre done :)
was that the answer u just did ?
yes :) \[8y^3(2y^2-3y-5)\]
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