Question

Calculate the slope of the tangent to the curve at the given point or value of x.
y=1/x , x=1/3

Answer 1

find the derivative, plug in 1/3

Answer 2

\[y=\frac{1}{x}\]
\[y'=-\frac{1}{x^2}\]

Answer 3

replace x by 1/3 get
\[y'=-\frac{1}{(\frac{1}{3})^2}=-9\]