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In algebra determine the nature of the solutions of the equation 7t^2-8t=0 Choose the solution A) 2 imaginary solutions B) 2 real solutions C) 1 real solution
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B
t(7t-8)=0 t = 0, 8/7 two real solutions
the only possible way for it to have complex solutions is for it to have a constant term. because the quadratic formula contains : \[\sqrt{ b^2-4ac} \] the only way for the part under the sqrt to be negative is for the expression to have a constant term
if it just have x^2 and x then you just factor out x easy and if it doesnt have a x^2 then its not a quadratic, its a linear equation , and they can only have one soln
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