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OpenStudy (anonymous):
If x3-3x2-4x+16=(x-2)(x+3)(x-A)+Bx+C find the constants A , B and C
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OpenStudy (anonymous):
A = 4 and B-6!=0 and x = (-C-8)/(B-6)
OpenStudy (anonymous):
How do you do it bro?
OpenStudy (anonymous):
It takes too long to solve it. But you just solve for the constants. I used wolfram to help me get there. It's too long of a formula to solve it by hand. but if need be It will take too long to explain.
OpenStudy (anonymous):
thnks bro
OpenStudy (anonymous):
http://www.wolframalpha.com/input/?i=solve+x3-3x2-4x%2B16%3D%28x-2%29%28x%2B3%29%28x-A%29%2BBx%2BC http://www.wolframalpha.com This is the website if you want to you can check it out. sometimes it show's you how to solve it also.
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