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OpenStudy (anonymous):
4x < 2x + 1 <= 3x + 2
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OpenStudy (anonymous):
<= ??
OpenStudy (anonymous):
\[\le\]
OpenStudy (anonymous):
4x < 2x +1 4x-2x < 1 2x<1 x< 1/2 [ 2x + 1 \le 3x +1\] \[2x-3x \le 1-1\] \[-x \le 0\] \[x \ge 0\] \[0\le x < 1/2\]
OpenStudy (anonymous):
thanks
OpenStudy (anonymous):
can you help with another one?
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