Question

Find all the roots and check your answers.

49x^2-25=0

Answer 1

nobody answered u..ok wait...
\[49x^2-25=(7x)^2-(5)^2=(7x-5)(7x+5)\]
Therefore the roots are \[7x-5=0\implies x=5/7 \ and 7x+5=0\implies x=-5/7\].
So \[5/7\ and -5/7\ are \ two\ roots.\]